解方程组:(x-2)(y-1)=(x-2)(y+3)① (x-12)(y-14)=(x+12)(y-2)②这是一个方程组,求x= y=
问题描述:
解方程组:(x-2)(y-1)=(x-2)(y+3)① (x-12)(y-14)=(x+12)(y-2)②
这是一个方程组,求x= y=
答
(x-2)(y-1)=(x-2)(y+3) ①(x-12)(y-14)=(x+12)(y-2) ②xy-2y-x+2=xy-2y+3x-6xy-12y-14x+168=xy+12y-2x-24 4x-4y-4=012x+24y-192=0x-y-1=0x+2y-16=0下式减上式得:3y=15y=5x=6所以原式的解为:{x=...