化简求值 (x²/1+y²/1+xy/2﹚÷x²y²/x+y 当x+y-2013=0(x²分之1+y²分之1+xy分之2﹚÷x²y²分之x+y

问题描述:

化简求值 (x²/1+y²/1+xy/2﹚÷x²y²/x+y 当x+y-2013=0
(x²分之1+y²分之1+xy分之2﹚÷x²y²分之x+y

友情提醒:/这个代表分数线,也代表除号,分数线左侧是分子,右侧是分母


(1/x²+1/y²+2/xy﹚÷(x+y)/x²y
=(1/x+1/y)²*x²y²/(x+y)
=[(x+y)/xy]²*x²y²/(x+y)
=(x+y)²/x²y²*x²y²/(x+y)
=x+y

当x+y-2013=0时,x+y=2013

(x²分之1+y²分之1+xy分之2﹚÷x²y²分之x+y=(1/x+1/y)²×x²y²/(x+y)=(x+y)²/(x²y²)×x²y²/(x+y)=x+y;=2013;很高兴为您解答,skyhunter002为您答疑...