1200+4y=500x 2400+20x=20y
问题描述:
1200+4y=500x 2400+20x=20y
答
1200+4y=500x.(1)
2400+20x=20y.(2)
(1)式移项,得1200=500x-4y.(3)
(2)+(3)X5得
2400+20x+6000=20y+2500x-20y
化简,得8400+20x=2500x,
∴x=8400/2480=105/31
y=3720/31