根号2x-y-8+根号x+2y+1=0 求xy.

问题描述:

根号2x-y-8+根号x+2y+1=0 求xy.

根号2x-y-8+根号x+2y+1=0
得到2x-y-8=0且x+2y+1=0
所以x=3,y=-2
xy=-6