cu2s+HN03=CU(N03)2+NO+H2S04+H20把它配平

问题描述:

cu2s+HN03=CU(N03)2+NO+H2S04+H20把它配平

(1)Cu2S ====> 2Cu(NO3)2 + H2SO4 ---升高10价!2Cu+ ====> 2Cu2+ --- 升高2价 *3!S2- =====> H2SO4 --- 升高8价 *3!(2)HNO3 ====> NO -------降低3价 *10!(3)生成6Cu(NO3)2---消耗12HNO3(4)3Cu2S + 22HNO3 == 6Cu(NO...