9(x-2)- 6(x-2)+1=0,则x-2=
问题描述:
9(x-2)- 6(x-2)+1=0,则x-2=
答
9(x-2)- 6(x-2)+1=0 [3(x-2)- 1]=0 3(x-2)- 1=0 3(x-2)=1 x-2=1/3
9(x-2)- 6(x-2)+1=0,则x-2=
9(x-2)- 6(x-2)+1=0 [3(x-2)- 1]=0 3(x-2)- 1=0 3(x-2)=1 x-2=1/3