9(x-2)- 6(x-2)+1=0,则x-2=

问题描述:

9(x-2)- 6(x-2)+1=0,则x-2=

9(x-2)- 6(x-2)+1=0 [3(x-2)- 1]=0 3(x-2)- 1=0 3(x-2)=1 x-2=1/3