关于x的不等式 (3x2++2x+2)/(x2+x+1)

分类: 作业答案 • 2022-04-05 10:59:13

问题描述：

数学人气：700 ℃时间：2020-05-20 02:09:42

优质解答

(3x2++2x+2)/(x2+x+1)
=2+x^2/(x^2+x+1)
=2+1/(1+1/x+1/x^2)
=1+1/[(1/x+1/2)^2+3/4]
≤1+1/(3/4)
=1+4/3
=7/3
m>7/3

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答

(3x2++2x+2)/(x2+x+1)
=2+x^2/(x^2+x+1)
=2+1/(1+1/x+1/x^2)
=1+1/[(1/x+1/2)^2+3/4]
≤1+1/(3/4)
=1+4/3
=7/3
m>7/3