若(x-y-1)2+|3x+2y-1|=0,则点P(x,y)在第_象限.
问题描述:
若(x-y-1)2+|3x+2y-1|=0,则点P(x,y)在第______象限.
答
∵(x-y-1)2+|3x+2y-1|=0,
∴
,
x−y−1=0 3x+2y−1=0
解得x=0.6,y=-0.4,
∴点P(x,y)在第四象限.故答案填:四.