一元四次方程求解..
问题描述：
一元四次方程求解..
x^4-20x^3+232x^2+1320x+4353.5=0
答
x^4-20 x^3+232 x^2+1320 x+4353.5 = 0((x-24.83194629620492933) x+339.1501329430093285) (x (x+4.831946296204930213)+12.836497990497797142) = 0FullSimplify[4353.5 + 1320 x + 232 x^2 - 20 x^3 + x^4 == 0](...