已知:A=3a2-4ab,B=a2+2ab. (1)求A-2B; (2)若|2a+1|+(2-b)2=0,求A-2B的值; (3)试将a2-2ab用A与B的代数式表示出来.

问题描述:

已知:A=3a2-4ab,B=a2+2ab.
(1)求A-2B;
(2)若|2a+1|+(2-b)2=0,求A-2B的值;
(3)试将a2-2ab用A与B的代数式表示出来.

(1)原式=(3a2-4ab)-2(a2+2ab)=3a2-4ab-2a2-4ab=a2-8ab;(2)根据题意得|2a+1|=0,(2-b)2=0,∴2a+1=0,2-b=0,∴a=-12,b=2,∴A-2B=(-12)2-8×(-12)×2=14+8=334;(3)∵A=3a2-4ab,B=a2+2ab,∴2A=6...