1.25*2.7+12.5*0.32+0.125*41分之2005/2006*2007

问题描述:

1.25*2.7+12.5*0.32+0.125*41分之2005/2006*2007
急QUQ。..........

(1.25*2.7+12.5*0.32+0.125*41)分之2005/2006*2007
=(1.25*2.7+1.25*3.2+1.25*4.1)分之2005/2006*2007
=(1.25*10)分之2005*2007/2006
=12.5分之2005*(2006+1)/2006
=1604(1+1/2006)
=1604+802/1003
=1604又802/1003我那个写错了,是1.25*2.7+12.5*0.32+0.125*41又2006分之2005*2007(1.25*2.7+12.5*0.32+0.125*41)又2006分之2005*2007=(1.25*2.7+1.25*3.2+1.25*4.1)+2005*2007/2006=(1.25*10)+(2006-1)*(2006+1)/2006=12.5+2006-1/2006=12+2006+1003/2006-1/2006=2018+501/1003=2018又501/1003