一道数学题,有难度哦.
问题描述：
一道数学题,有难度哦.
若a = 三次根号4+三次根号2+三次根号1,求3/a+3/axa(两个a相乘的啊）+1/axaxa(三个a相乘)的值是?
答
已知 a=三次根号4+三次根号2+1.则3/a+3/a^2+1/a³=____a = 4^(1/3) + 2^(1/3) + 1令 x = 2^(1/3)则 a = x² + x + 1a (x - 1) = (x - 1)(x² + x + 1) = x³ - 1 = 2 - 1 = 1所以：x = 1 + 1/a3/a +...