若&,@均为锐角且tan&=1/2,tan@=1/3,则&+@=

问题描述:

若&,@均为锐角且tan&=1/2,tan@=1/3,则&+@=

tan(A+B)
=(tanA+tanB)/(1-tanAtanB)
=(1/2+1/3)/(1-1/2 *1/3)
=(5/6)/(5/6)
=1
&+@=A+B=π/4