某批产品中有20%的不合格品,进行重复抽样检查,共取5个样品,其中不合格品数为X,试确定X的概率分布?

P(X=i)=C(5,i)*0.2^i*0.8^(5-i)P(X=0)=0.8^5=0.32768P(X=1)=C(5,1)*0.2*0.8^4=0.4096P(X=2)=C(5,2)*0.2^2*0.8^3=0.2048P(X=3)=C(5,3)*0.2^3*0.8^2=0.0512P(X=4)=C(5,4)*0.2^4*0.8=0.0064P(X=5)=0.2^5=0.00032