(-2013又7/6)+(-2012又2/3)+4025又2/3+(-1又1/2)用拆项法
问题描述:
(-2013又7/6)+(-2012又2/3)+4025又2/3+(-1又1/2)用拆项法
答
= -1005-2004 4010 +1-5/6 -2 / 3 2/3 1/2 = 1002-1/3 = 1001和2/3
(-2013又7/6)+(-2012又2/3)+4025又2/3+(-1又1/2)用拆项法
= -1005-2004 4010 +1-5/6 -2 / 3 2/3 1/2 = 1002-1/3 = 1001和2/3