sin3分之25兀+cos4分之17兀+tan6分之23兀

分类: 作业答案 • 2022-03-27 20:40:56

问题描述：

答

sin3分之25兀+cos4分之17兀+tan6分之23兀
=sin25π/3+cos17π/4+tan23π/6
=sin(8π+π/3)+cos(4π+π/4)+tan(4π-π/6)
=sinπ/3+cosπ/4-tanπ/6
=√3/2+√2/2-√3/3
=(√3+3√2)/6