求解七元一次方程组,
问题描述：
求解七元一次方程组,
34.04x1+54.96x2+14.22x3+9.03x4+53.46x5+x6-1.5507x7=0
34.66x1+54.83x2+13.99x3+9.03x4+55.00x5+x6-1.5613x7=0
34.39x1+56.29x2+14.09x3+9.03x4+54.33x5+x6-1.5678x7=0
33.89x1+54.40x2+14.48x3+8.98x4+54.62x5+x6-1.5500x7=0
34.41x1+57.20x2+14.19x3+8.87x4+56.51x5+x6-1.5808x7=0
34.68x1+59.00x2+14.48x3+9.07x4+58.02x5+x6-1.6111x7=0
34.91x1+56.86x2+14.40x3+9.08x4+57.25x5+x6-1.5935x7=0
以上x1,x2,---x7,都是未知数,请别误认作乘号.请帮忙算算,
答
-2M1
2X-Y=5+M 所以4X-2Y=10+2M 所以4X-2Y++X+2Y=10+2M+3M 5X=10+5M X=2+M 2+M0 M-2
2+M+2Y=3M Y=M-1 M-10 M1 所以-2M1