怎么解一元二次方程(x-根号3）^2=4x+12-4根号3?
问题描述：
怎么解一元二次方程(x-根号3）^2=4x+12-4根号3?
答
(x-根号3）^2=4x+12-4根号3 (x-根号3）^2-4(x-根号3)-12=0 (x-根号3+2)(x-根号3-6)=0 x-根号3+2=0 x-根号3-6=0 x=根号3-2 x=根号3+6
怎么解一元二次方程(x-根号3）^2=4x+12-4根号3?
(x-根号3）^2=4x+12-4根号3 (x-根号3）^2-4(x-根号3)-12=0 (x-根号3+2)(x-根号3-6)=0 x-根号3+2=0 x-根号3-6=0 x=根号3-2 x=根号3+6