不改变分式的值,把下列分式的分子分母中各项系数化为整数 1.0.2x+y/0.1x-0.3y
问题描述:
不改变分式的值,把下列分式的分子分母中各项系数化为整数 1.0.2x+y/0.1x-0.3y
2.0.5x+0.25y/0.5x-1/3y
答
1.0.2x+y/0.1x-0.3y
=(1/5x+y)/(1/10x-3/10y)
=[(x+5y)*1/5]/[(x-3y)*1/10]
=2(x+5y)/(x-3y)
2.0.5x+0.25y/0.5x-1/3y
=(1/2x+1/4y)/(1/2x-1/3y)
=[(2x+y)*1/4]/[(3x-2y)*1/6]
=3(2x+y)/2(3x-2y)