先约分,再求值:3+2a-a² 除以 a²-7a+12.a=-2分之1
问题描述:
先约分,再求值:3+2a-a² 除以 a²-7a+12.a=-2分之1
答
﹙3﹢2a-a²﹚/﹙a²-7a﹢12﹚
=[﹣﹙a²-2a-3﹚]/﹙a²-7a﹢12﹚
=[﹣(a-3)(a﹢1)]/(a-4)(a-3)
=﹣(a﹢1)/(a-4)
=﹣(﹣½﹢1)/(﹣½-4)
=1/9