2/x^2-4-1/x+2=0(分式方程)怎么做?
问题描述:
2/x^2-4-1/x+2=0(分式方程)怎么做?
答
解
2/(x²-4)-1/(x+2)=0
两边乘以x²-4=(x-2)(x+2)得:
2-(x-2)=0
2-x+2=0
∴x=4
经检验x=4是方程的根