解一个方程组.20x+15y+25(y-0.6)=145 20x+20(x-0.4)+15y+5(y-0.6)=129
问题描述:
解一个方程组.20x+15y+25(y-0.6)=145 20x+20(x-0.4)+15y+5(y-0.6)=129
20x+15y+25(y-0.6)=145
20x+20(x-0.4)+15y+5(y-0.6)=129
答
解题得:
x=2
y=3请问有过程吗。解题过程20X+15y+25y-15=145 (1)20x+40y=16020x+20x-8+15y+5y-3=129 40x+20y=140(2)20x+10y=70式1-式2得30y=90y=3代入可得x=2