方┡ 21=1000A +100B

问题描述:

方┡ 21=1000A +100B
程┡
组┡46.5=72500A+150B
:A=
B=

"21=1000A +100B"两边同时乘以3①式子为63=3000A+300B
“46.5=72500A+150B”两边同时乘以2 ②式子为93=145000A+300B
再拿②-①,得:142000A=30 A=14200分之3
把B代入① B=1775分之369