x+y=57 (1+80%)x+(1+90%)y=470
问题描述:
x+y=57 (1+80%)x+(1+90%)y=470
x+y=57是一个方程,(1+80%)x+(1+90%)y=470是另一个方程,合起来是一个方程组,
答
消元法:1.8x+1.8y=57x1.8=102.6(1)(1+80%)x+(1+90%)y=470(2)
用(2)—(1)得,0.1y=470-102.6=367.4
y=3674又
x+y=57得出x=_3617