(2+1)*(2¤2+1)*(2¤4)*(2¤8+1)*(2¤16+1)*(2¤64+1)+1的末位数是?(注¤是幂).
问题描述:
(2+1)*(2¤2+1)*(2¤4)*(2¤8+1)*(2¤16+1)*(2¤64+1)+1的末位数是?(注¤是幂).
答
=(2-1)(2+1)*(2¤2+1)*(2¤4)*(2¤8+1)*(2¤16+1)*(2¤64+1)+1
=2¤128-1+1
=2¤128
2¤1=2
2¤2=4
2¤3=8
2¤4=16
2¤5=32 末尾是周期循环的周期为4 128/4=32
末尾应该为6