(x2-4x+4分之x2-4加x+2分之2-x)÷x-2分之x

问题描述:

(x2-4x+4分之x2-4加x+2分之2-x)÷x-2分之x

原式=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)]×(x-2)/x
=[(x+2)/(x-2)-(x-2)/(x+2)]×(x-2)/x
=[(x²+4x+4-x²+4x-4)/(x-2)(x+2)]×(x-2)/x
=[8x/(x-2)(x+2)]×(x-2)/x
=8/(x+2)