因式分解:x(x-1)(x+2)(x+3)-40.
问题描述:
因式分解:x(x-1)(x+2)(x+3)-40.
答
原式=[x(x+2)][(x-1)(x+3)]-40
=(x2+2x)(x2+2x-3)-40
=(x2+2x)2-3(x2+2x)-40
=(x2+2x+5)(x2+2x-8)
=(x2+2x+5)(x-2)(x+4).