设集合A={(x,y)|a1x+b1x+c1=0},B={(x,y)|a2x+b2x+c2=0},则方程(a1x+b1x+c1)(a2x+b2x+c2)=0的解集为_.
问题描述:
设集合A={(x,y)|a1x+b1x+c1=0},B={(x,y)|a2x+b2x+c2=0},则方程(a1x+b1x+c1)(a2x+b2x+c2)=0的解集为______.
答
∵集合A={(x,y)|a1x+b1x+c1=0},B={(x,y)|a2x+b2x+c2=0},
∴方程(a1x+b1x+c1)(a2x+b2x+c2)=0的解集为A∪B.
故答案为:A∪B