[1+﹙2x-4﹚/﹙x+1﹚﹙x-2﹚]÷[x+3/x2-1]其中x等于6
问题描述：
[1+﹙2x-4﹚/﹙x+1﹚﹙x-2﹚]÷[x+3/x2-1]其中x等于6
答
[1+﹙2x-4﹚/﹙x+1﹚﹙x-2﹚]÷[x+3/x²-1]
=[1+2/(x+1)]×(x²-1)/(x+3)
=(x+3)/(x+1)×(x+1)(x-1)/(x+3)
=x-1
=6-1
=5