函数f(x)=sinx^2+cos(x-π /3)^2的单调增区间是
问题描述：
函数f(x)=sinx^2+cos(x-π /3)^2的单调增区间是
答
f(x)=sin²x+cos²(x-π/3)=[1-cos(2x)]/2 +[1+cos(2x-π/3)]/2 /二倍角公式=(1/2)[cos(2x-2π/3)-cos(2x)] +1=(1/2)[cos(2x)cos(2π/3)+sin(2x)sin(2π/3) -cos(2x)]+1=(1/2)[(-1/2)cos(2x)+(√3/2)sin(2x)...