x+y=12,xy=4,则x-y=(
问题描述:
x+y=12,xy=4,则x-y=(
答
x-y=正负根号下(x-y)^2; (x-y)^2=x^2+y^2-2xy=12-8=4; x-y=正负2
x+y=12,xy=4,则x-y=(
x-y=正负根号下(x-y)^2; (x-y)^2=x^2+y^2-2xy=12-8=4; x-y=正负2