(cot60°-sin60°)÷(cos45°+1/2 tan45°-cot30°)大神们帮帮忙
问题描述:
(cot60°-sin60°)÷(cos45°+1/2 tan45°-cot30°)大神们帮帮忙
答
原式=(根号3/3-根号3/2)/(1/2+1/2-根号3) =(-根号3/6) /(1-根号3) =(3+根号3)/12
(cot60°-sin60°)÷(cos45°+1/2 tan45°-cot30°)大神们帮帮忙
原式=(根号3/3-根号3/2)/(1/2+1/2-根号3) =(-根号3/6) /(1-根号3) =(3+根号3)/12