(x1-x2)-[a(x1+x2)]/x1x2 这个要怎么化简啊?怎么变成这样[(x1-x2)(x1x2-a)]/x1x2?
问题描述:
(x1-x2)-[a(x1+x2)]/x1x2 这个要怎么化简啊?怎么变成这样[(x1-x2)(x1x2-a)]/x1x2?
答
(x1-x2)-[a(x1+x2)]/x1x2 要等于[(x1-x2)(x1x2-a)]/x1x2,
必须把[a(x1+x2)]中的+变成-
即(x1-x2)-[a(x1-x2)]/x1x2 =[(x1-x2)(x1x2-a)]/x1x2