求值(log43+log83)(log32+log92) 注：log后面那为数是底数,最好用通俗易懂的解法.
问题描述：
求值(log43+log83)(log32+log92) 注：log后面那为数是底数,最好用通俗易懂的解法.
答
换底公式轻松解决：
原式=
(log3/log4+log3/log8)(log2/log3+log2/log9) （log是10为底）
=(log3/(2log2)+log3/(3log2))(log2/log3+log2/(2log3))
=5/6*log3/log2*3/2*log2/log3
=5/4