-x^3-3x^2+10x+24=0
问题描述：
-x^3-3x^2+10x+24=0
答
X=3或-4把邮箱给我,我给你发过程稍等我给你写过程去 -x3-3x2+10x+24=0(x3-1)+(3x2-3)-(10x+20)=0(x-1)(x2+x+1)+3(x+1)(x-1)=10(x+2)(x-1)(x2+x+1+3x+3)=10(x+2)(x-1)(x2+4x+4)=10(x+2)(x-1)(x+2)2=10(x+2)(x-1)(x+2)...