麻烦帮我解答:1.x(-x-11)=___,(-1-4x)(1-4x)=__.

问题描述:

麻烦帮我解答:1.x(-x-11)=___,(-1-4x)(1-4x)=__.
2.(a-b+1)²=(a-b)²+___=a²-2ab+___。
3.已知x(x-1)-(x²-y)=-3,求x²+y²-2xy的值(要过程的,
4.已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)÷2y的值。

1.x(-x-11)=-x²-11x
2.(-1-4x)(1-4x)=-1+4x-4x+16x²=16x²-1我还发了几个问题,麻烦再帮我解答!2.(a-b+1)²=(a-b)²+2×1×(a-b)+1²=a²-2ab+b²+2a-2b+13.x²-x-x²+y=3 y-x=-3 x-y=3x²+y²-2xy =(x-y)² =3² =94.2x-y=10 变为 y=2x-10 [(x²+y²)-(x-y)²+2y(x-y)]/2y =[(x²+(2x-10)²)-(x-(2x-10))²+2(2x-10)(x-(2x-10)]/2y =[(x²+(4x²-40x+100))-(-x+10)²+(4x-20)(-x+10)]/(4x-20) =[(x²+4x²-40x+100)-(x²-20x+100)+(-4x²+40x+20x-200)]/(4x-20) =(40x-200)/(4x-20) =10(4x-20)/(4x-20) =10 步骤就是将y=2x-10 代入要求的公式里 、 我写的有点复杂 、希望你看得懂吧那哪里可以省略一点我省了:4.2x-y=10 变为 y=2x-10 [(x²+y²)-(x-y)²+2y(x-y)]/2y =[(x²+(2x-10)²)-(x-(2x-10))²+2(2x-10)(x-(2x-10)]/2y =[(x²+4x²-40x+100)-(x²-20x+100)+(-4x²+40x+20x-200)]/(4x-20) =(40x-200)/(4x-20) =10(4x-20)/(4x-20) =10 差不多了,不能再省求采纳,记得给分哟