√3sin2x+cos2x=2sin(2x+π/6)请问这类变化怎么推导…要详细的步骤和说明~
问题描述:
√3sin2x+cos2x=2sin(2x+π/6)
请问这类变化怎么推导…要详细的步骤和说明~
答
√3sin2x+cos2x
=2*(√3/2sin2x+1/2cos2x)
=2*(sin2xcosπ/6+cos2xsinπ/6)
=2sin(2x+π/6)