—x的4次方y的4次方—81分之1+x²y²,分解因式,
问题描述:
—x的4次方y的4次方—81分之1+x²y²,分解因式,
答
原式:-x^4y^4+x2y2-1/81
原式等于:(-1/81+1/4)-(x^4y^4-x2y2+1/4)
即:71/324-(x²y²-1/2)²=[(√71)/18-x²y²+1/2]×[(√71)/18+x²y²-1/2]
进一步分-(xy-√((√71)/18+1/2))(xy+√((√71)/18+1/2))(xy-√(-(√71)/18+1/2))(xy+√(-(√71)/18+1/2))