已知(x+3)2+1x-y+101=0,求5x2y-[2x2y-(3xy-xy)2-3x2]-2xy-y2

问题描述:

已知(x+3)2+1x-y+101=0,求5x2y-[2x2y-(3xy-xy)2-3x2]-2xy-y2

因为(x+3)^2+|x-y+10|=0,
且(x+3)^2≥0,|x-y+10|≥0,
所以x+3=0,x-y+10=0,
所以x=-3,y=7,
化简后再代入求值.