求40+(x-60)*0.2=60+(x-200)*0.3
问题描述:
求40+(x-60)*0.2=60+(x-200)*0.3
答
40+(x-60)*0.2=60+(x-200)*0.3
40+0.2x-12=60+0.3x-60
0.3x-0.2x=40-12
0.1x=28
x=28÷0.1
x=280