您的位置: 首页  >  作业答案  >  数学  >  求大师计算啊[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²=[9x²y²*x^4-2x²*9x²y^4*(y/2)]/(9x^4y²=[x^4(9x²y²)-2x²(9x²y^4)*(y/2)]/(9x^4y²)=[x^4(9x²y²)-2x²y²(9x²y²)*(y/2)]/(9x²y²)x²=[(9x²y²)(x^4-2x²y²)*(y/2)]/(9x²y²)x²=[(x^4-2x²y²)*(y/2)]/x²=[x²(x²-2y²)*(y/2)]/x²=(x²-2y²)*(y/2)=[ ( x² - 2y² ) y ] / 2对吗还有更简便的方法吗

求大师计算啊[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²=[9x²y²*x^4-2x²*9x²y^4*(y/2)]/(9x^4y²=[x^4(9x²y²)-2x²(9x²y^4)*(y/2)]/(9x^4y²)=[x^4(9x²y²)-2x²y²(9x²y²)*(y/2)]/(9x²y²)x²=[(9x²y²)(x^4-2x²y²)*(y/2)]/(9x²y²)x²=[(x^4-2x²y²)*(y/2)]/x²=[x²(x²-2y²)*(y/2)]/x²=(x²-2y²)*(y/2)=[ ( x² - 2y² ) y ] / 2对吗还有更简便的方法吗

分类: 作业答案 • 2021-12-19 11:02:24
问题描述：

求大师计算啊[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²
[(-3xy)²*x^4-2x²(3xy²)²*(y/2)]/(-3x²y)²
=[9x²y²*x^4-2x²*9x²y^4*(y/2)]/(9x^4y²
=[x^4(9x²y²)-2x²(9x²y^4)*(y/2)]/(9x^4y²)
=[x^4(9x²y²)-2x²y²(9x²y²)*(y/2)]/(9x²y²)x²
=[(9x²y²)(x^4-2x²y²)*(y/2)]/(9x²y²)x²
=[(x^4-2x²y²)*(y/2)]/x²
=[x²(x²-2y²)*(y/2)]/x²
=(x²-2y²)*(y/2)
=[ ( x² - 2y² ) y ] / 2


对吗
还有更简便的方法吗

答

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