①(0.25^2008)*(4^2009)-(8^100)*0.5^300得多少 ②(0.125^3)*(0.25^3)*(2^6)*2^12
问题描述：
①(0.25^2008)*(4^2009)-(8^100)*0.5^300得多少 ②(0.125^3)*(0.25^3)*(2^6)*2^12
答
①(0.25^2008)*(4^2009)-(8^100)*0.5^300
=(0.25^2008)*(4^2008)*4-(2^300)*0.5^300
=(0.25*4)^2008*4-(2*0.5)^300
=1^2008 *4- 1^300
=4-1
=3
②(0.125^3)*(0.25^3)*(2^6)*2^12
=(0.125^3)*(0.25^3)*(4^3)*8^4
=(0.125^3)*(0.25^3)*(4^3)*8^3*8
=(0.125×8)^3*(0.25*4)^3*8
=1*1*8
=8