请问如何计算斐波那契数列（0.1.1.3.5.）第n项的值,其中n
问题描述：
请问如何计算斐波那契数列（0.1.1.3.5.）第n项的值,其中n
数学人气：500 ℃时间：2020-08-27 04:23:40
优质解答
F(n)=(1/√5)*{[(1+√5)/2]^(n+1) - [(1-√5)/2]^(n+1)}.1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269,2178309...
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答
F(n)=(1/√5)*{[(1+√5)/2]^(n+1) - [(1-√5)/2]^(n+1)}.1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368,75025,121393,196418,317811,514229,832040,1346269,2178309...