解复变函数方程(z+i)*5=1
问题描述：
解复变函数方程(z+i)*5=1
答
z+i=cos(2kπ/5+isin2kπ), k=0,1,2,3,4,
z=cos(2kπ/5+isin2kπ)-i, k=0,1,2,3,4,
答
(z+i)^5=1
(z+i)^5=e^(i0)
z+i=e^i(2kπ/5),
z=cos(2kπ/5+isin(2kπ/5)-i, k=0,1,2,3,4