因式分解：x²-3xy-10y²+x-5y

分类: 作业答案 • 2022-02-26 13:43:44

问题描述：

答

原式=(x+2y)(x-5y)+(x-5y)
=(x-5y)(x+2y+1)

答

因式分x²-3xy-10y²+x-5y
原式=(x-5y)(x+2y)+(x-5y)=(x-5y)(x+2y+1)

答

解:x^2-3xy-10y^2+x-5y
=(x-5y)(x+2y)+x-5y
=(x-5y)(x+2y+1)

答

x²-3xy-10y²+x-5y
=(x-5y)(x+2y)+(x-5y)
=(x-5y)(x+2y+1)

答

x²-3xy-10y²+x-5y
=(x-5y)(x+2y)+(x-5y)
=(x-5y)(x+2y+1)