一只蝙蝠以6m/s的速度垂直于竖直墙水平飞行,同时向墙发射超声波,经0.1s接到回声.设声速为340m/s,求蝙蝠接到回声时离墙多远?

问题描述:

一只蝙蝠以6m/s的速度垂直于竖直墙水平飞行,同时向墙发射超声波,经0.1s接到回声.设声速为340m/s,求蝙蝠接到回声时离墙多远?

0.1s*340m/s=34m
6m/s*0.1s=0.6m
34m/2=14m
14m-0.6m=13.4m

(340-6)X0.1除以二。
答案你自己算。

S1=v1t=340m/s*0.1s=34m
S2=v2t=6m/s*0.1s=0.6m
l=(S1-S2)/2=(34m-0.6m)/2=16.7m