先去括号,再合并同类项.x-(3x-2)+(2x-3); (3a的2次方+a-5)-(4-a+7a的2次方)

问题描述:

先去括号,再合并同类项.x-(3x-2)+(2x-3); (3a的2次方+a-5)-(4-a+7a的2次方)

x-(3x-2)+(2x-3)
=x-3x+2+2x-3
=x-3x+2x+2-3
=-1
(3a的2次方+a-5)-(4-a+7a的2次方)
=3a²+a-5-4+a-7a²
=3a²-7a²+a+a-5-4
=-4a²+2a-9

x-(3x-2)+(2x-3)
=x-3x+2+2x-3
=-1
(3a的2次方+a-5)-(4-a+7a的2次方)
=3a²+a-5-4+a-7a²
=-4a²+2a-9