解方程(y-2)(2y-1)=1-2y好急好急好急好急

问题描述:

解方程(y-2)(2y-1)=1-2y
好急好急好急好急

(y-2)(2y-1)+(2y-1)=0
(y-2+1)(2y-1)=0
y=1或y=1/2

(y-2)(2y-1)=1-2y
(y-2)(2y-1)+(2y-1)=0
(y-1)(2y-1)=0
y=1或y=0.5

(y-2)(2y-1)-(1-2y)=0
(y-2)(2y-1)+(2y-1)=0
(y-2+1)(2y-1)=0
(y-1)(2y-1)=0
y=1
y=1/2