已知(x+2)的四次方+y-1的绝对值=0,求5xy-【4x²y-(-3xy²+2x²+2x²y)】的值

问题描述:

已知(x+2)的四次方+y-1的绝对值=0,求5xy-【4x²y-(-3xy²+2x²+2x²y)】的值

四次方和绝对值都为非负值,应此x=-2,y=1。代入得-4

(x+2)的四次方+y-1的绝对值=0(x+2)的四次方=0,y-1的绝对值=0x=-2y=15xy-【4x²y-(-3xy²+2x²+2x²y)】=5xy-【4x²y+3xy²+2x²+2x²y】=5xy-【4x²y+2x²y+3xy²...