怎样计算下列各题~①1/2＋1/4＋1/6＋1/31＋1/62＋1/124＋1/248＋1/496②1/42＋5/42＋11/42＋13/42＋17/42＋19/42＋23/42＋25/42＋29/42＋31/42＋37/42＋41/42
问题描述：
怎样计算下列各题~
①1/2＋1/4＋1/6＋1/31＋1/62＋1/124＋1/248＋1/496
②1/42＋5/42＋11/42＋13/42＋17/42＋19/42＋23/42＋25/42＋29/42＋31/42＋37/42＋41/42
答
①1+1/2+1/4+1/8+1/16=2-1/16=31/161/2＋1/4＋1/6=11/121/31＋1/62＋1/124＋1/248＋1/496=1/31×(1+1/2+1/4+1/8+1/16)=1/31×31/16=1/16所以,1/2＋1/4＋1/6＋1/31＋1/62＋1/124＋1/248＋1/496=31/16+1/16=2② 1 5 ...